A local hamburger shop sold a combined total of 613 hamburgers and cheeseburgers on Wednesday. There were 63 more cheeseburgers sold than hamburgers. How many hamburgers were sold Wednesday

This problem can be solved through the creation of a system of equations relating the number of hamburgers (x) and cheeseburgers (y).

Having a combined total of 603 hamburgers and cheeseburgers can be written as x+y=603 and having 53 more cheeseburgers than hamburgers can be written algebraically as y=x+53.

To solve the system:

x+y=603

y=x+53

Substitute what y equals in the second equation for y in the first equation:

x+(x+53)=603

2x+53=603

  -53    -53

2x=550

2    2

x=275 hamburgers

To solve for the number of cheeseburgers, substitute 275 for x in either equation.

y=x+53

y=275+53

y=328 cheeseburgers

To double check your work, make sure that 275+328=603 and that 328=275+53. Since both are true, you have solved for the number of hamburgers (275) and cheeseburgers (328).

Step-by-step explanation:

58 cheeseburgers

Step-by-step explanation:

i need more details sorry

step-by-step explanation: