OMG PLS HELP I'LL MARK BRAINLIEST select the correct answer from each drop down menu:

A sequence of transformations maps A'B'C' to ABC The sequence of transformations that maps ABCto A'B'C' is a reflection across the _ (options: y-axis, x-axis, line y=x, line y=-x) followed by a translation_ (options: 4 units to the right and 10 units up, 8 units to the right 4 units up, 10 units to the right and 2 units up, 10 units to the right and 4 units up).

The shape of A'B'C' is a reflection across the line y=x

followed by a translation of 10 units to the right and 4 units up

Hope this helped!

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3