I need help with this one.

2x³ = x • 2x², and

2x² (x + 3) = 2x³ + 6x²

Subtract this from the dividend to get a remainder of

(2x³ + 4x² - 5) - (2x³ + 6x²) = -2x² - 5

-2x² = x • (-2x), and

-2x (x + 3) = -2x² - 6x

Subtract this from the last remainder to get a new one of

(-2x² - 5) - (-2x² - 6x) = 6x - 5

6x = x • 6, and

6 (x + 3) = 6x + 18

This gives a new remainder of

(6x - 5) - (6x + 18) = -23

x does not divide -23, so we're done, leaving us with

where r the answers

step-by-step explanation:

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)