Which sequence of steps is a correct derivation of the difference quotient for f(x) = 3 – log x?

Step-by-step explanation:

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Still, it's possible to help you without your having shared those choices.

The "difference quotient" is defined as:

 f(x + h) - f(x)

           h

where h represents an incremental (small) change in x.

Here f(x) = 3 - log x, and so f(x + h) = 3 - log (x + h).

Therefore the difference quotient is:

{3 - log (x + h)} - {3 - log x}

                    h

This can be simplified.  In the numerator we have 3 - 3, so the numerator simplifies to -log (x + h) + log x

and the difference quotient is

-log ( x + h) + log x

              h

This can be rewritten as

log x - log (x + h)                                x                                  x

, or (1/h)*log , or  (1/h) log { }

              h                                       (x + h)                            x + h          

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?