Find two positive and two negative angles that are coterminal with the quadrantal angle such that each angle lies between 1080 and 720

The quadrantal angles are those whose terminal side lands on an axis.

The general form of these angles is:

A = n*90°.

Where n can be any integer.

Now we want to two negative angles and two positive angles, such that the angles lie between 1080 and 720.

As the number in the left is, in absolute value, larger than 720, i guess that the segment is written as:

-1080 and 720.

This also will allow us to find the negative angles that we want.

Now, first find the positive ones.

A = n*90°

Just give n the value of positive integers, for example, 7 and 6

A = 7*90° = 630°

A = 6*90° = 540°.

And for the negative angles, we need to input negative values for n.

let's take n = -8 and -9

A = -8*90° = -720°

A = -9*90° = -810°.

And all those angles are in the given range.

he can buy 4lbs. of live bait and 1lbs of natural bait

step-by-step explanation:

step-by-step explanation:

why? because i noticed a pattern. 60 120. those numbers without the zero, make the 6 times tables leaving your answer to be b since 6 times 4 is 24 and adding a zero making it 240.