A hotel purchases a large photo for its newly renovated lobby. The perimeter of the photo is 234 in. The width is 6 in. more than twice the height. Find the dimensions of the photo.

Step-by-step explanation:

in this problem we are expected to find the length/height of the photo

given

perimeter= 234in

let the height be x

width = 2x+6"The width is 6 in. more than twice the height."

we know that the perimeter is expressed as

P=2H+2W

P=2(x)+2(2x+6)

234=2(x)+2(2x+6)

solving for x we have

234=2x+4x+12

234-12=6x

222=6x

x=222/6

x=37in

the height is 37in

put x=37 in width = 2x+6

width = 2(37)+6

width = 74+6

width = 80in

answer: i think it is (1,-2)

9 x 8 divided by (5-3)=36