DeShaun and Vu are brothers who like to make bets about the outcomes of different contests between them. Before the last bet, the ratio of the amount of Deshaun's money to the amount of Vu's money was 4:7. Vu lost the latest competition, and now the ratio of the amount of Vu's money is 8:3. If Vu had $280 before the last competition, how much does Vu have now that he lost the bet?

Vu have $60.

Step-by-step explanation:

Given: Before bet, the ratio of the amount of Deshaun's money to the amount of Vu's money was 4:7.

Let Deshaun's money =4x and Vu's money = 7x

If Vu had $280 before the last competition, then

7x = 280

⇒ x = 40   [Divide both sides by 7]

Deshaun's money = 4x = 4 x 40 = $160

After Vu lost bet, ratio becomes 8:3.

Let Deshaun's money = 8y and Vu's money = 3y

For Deshaun,  8x = 160 ⇒ y = 20  [divide both sides by 8]

Vu's money  = 3 (20)=$60

Hence, Vu have $60.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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