Terrence drove to his sister's house, a distance of d miles. For the first 150 miles, he was able to drive relatively quickly, at 60 miles per hour. For the remaining distance, the road was rougher, and he had to slow his speed by 20 miles per hour. For each part of the journey, he was able to keep a steady speed. The time he spent driving at the faster speed was twice the time he spent driving at the slower speed.

The total distance he drove is 350 miles, with an average speed of 46.67 miles/hour.

Step-by-step explanation:

Let and be the time of driving at a slower rate and at a faster rate respectively.

Given that the total distance = d

The speed for the first 150 miles = 60 miles/hour.

So, [ as distance = speed x time]

hours.

The remaining distance miles.

Speed for the remaining distance = 60 miles/hour.

As the time he spent driving at the faster speed was twice the time he spent driving at the slower speed,

So, the time of driving at a faster rate, hours

So, [ as distance = speed x time]

miles.

The average speed of the journey = (Total distance)/(Total time taken )

=350/(2.5+5)

=350/7.5

=46.67 miles/hour.

Hence, the total distance he drove is 350 miles, with an average speed of 46.67 miles/hour.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3