Paul is making a ball-toss game for his club booth at the fair. He wants to make the circumference of the holes at least 3 inches greater but not more than 4 inches greater than the circumference of the ball. One person suggests that Paul can make the diameter of the hole 1 inch greater than that of the ball. Another suggests the diameter should be 2inches greater. Which suggestion should Paul choose? Explain

Step-by-step explanation:

we are going to assume a diameter of the hole has 6in

the radius of the ball is 3in

we looking at a range of the hole greater by (3<4)

we know that the circumference of a circle is given as

the circumference of the ball is

C=2πr

C=2*3.142*3

C=18.85in

The circumference of the hole is ( 1 inch greater )

C=2πr

say the diameter is 6in plus 1in = 7in

the radius =3.5in

C=2*3.142*3.5

C=21.99

compare with the ball the difference is 21.99-18.85

=3.14 which is in the range

The circumference of the hole is ( 2inches greater. )

C=2πr

say the diameter is 6in plus 2in = 8in

the radius =4in

C=2*3.142*4

C=25.13in

compare with the ball the difference is 25.13-18.85

=6.28 which is out of  the range

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

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step-by-step explanation: