5. Determine the maximum number of real zeros. f
(x)=(x-1/3)^2(x-1)^3

The maximum number of real zeros of the function is 5.

Step-by-step explanation:

Zeros of a polynomial

Any polynomial of positive order can have a maximum number of zeros equal to its order. For example, a quadratic function can have as many as two zeros.

The given polynomial is:

The order of this polynomial is 5 since it's factored as a quadratic polynomial by a cubic polynomial. The order is 2+3=5.

Thus, the maximum number of real zeros of the function is 5.

2.   2 3/5.

3.   2 1/2.

step-by-step explanation:

6 - 3 2/5

= 6 -   17/5

= 30/5 - 17/5

= 13/5

= 2 3/5 (answer).

5 1/4 - 2 3/4

= 21/4 - 11/4

= 10/4

= 2 1/2 (answer).

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47