What is the perimeter of a regular pentagon with 2 consecutive vertices at (-1,2) and (3,-1)?

Thus, the perimeter of the regular pentagon is 25 units

Step-by-step explanation:

The perimeter of a regular pentagon of side length a is:

P = 5a

We know 2 consecutive vertices of a pentagon are the points (-1,2) and (3,-1). If we calculate the distance between them we'd have the value of a.

Given two points A(x1,y1) and B(x2,y2), the distance between them is:

Using the points of the vertices:

a = 5

Now we calculate:

P=5a=5*5=25

Thus, the perimeter of the regular pentagon is 25 units

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

y/x=18

step-by-step explanation: