The length of a new rectangular playing field is 2 yards longer then double the width. If the perimeter of the rectangular playing field is 322 yards, what are its dimensions?

Step-by-step explanation:

First, we want to take the information we have and turn it into an equation, where x is our unknown dimension. For this problem, it would be better if x was equal to the width.

Let's  write out the equation:

X is the width, 2x + 2 is the length, and we are multiplying both by two since there are two sides of the field. It will all equal to 322, because that is the perimeter.

2*x + 2(2x +2) = 322

Now, let's solve:

2*x + 2(2x + 2) = 322

2x + 4x + 4 = 322

6x + 4 = 322

6x = 318

x = 318 ÷ 6

x = 53

The width is 53 yards. To find the length, we multiply 53 by two and add two.

53 * 2 + 2 = 106 + 2 = 108 yards, as the length

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it