What are the values of x, and y?

if this came out of a book use slader

Step-by-step explanation:

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What are the values of x and y?

a) 3x + 5y = 26

b) 2x + 2y = 12

Step One: We need to find a way to equate either the x terms of the y terms in each equation. Multiply equation a) by 2 and equation b) by 3 to form the following equations.

a) 6x + 10y = 52

b) 6x + 6y = 36

Step Two: Take equation b) from equation a) to eliminate the x component.

a) 6x + 10y = 52

- b) 6x + 6y = 36

0x + 4y = 16

y = 4

Step Three: substitute the value of y into either equation to find the value of x.

b) 2x + 2y = 12

2x + (2x4) =12

2x + 8 = 12

2x = 4

x = 2

x=2 y=4

Step-by-step explanation:

thank you sana nakatulong yang sagot ko

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb