Answer to number 16 please

        x   |   y

1. |   0    |   2

2.|  -2    |   5

3.|    1    |   0.5

4.|    4   |   -4

Step-by-step explanation:

3x + 2y = 4

manipulate the literal equation

3x + 2y = 4

y = (4 - 3x)/2

now substitute in the given values and solve

x = 0

y = (4 - (3 * 0))/2

y = 2

x = -2

y  = (4 - (3 * -2))/2

y = 5

x = 1

y = (4 - (3 * 1))/2

y = 0.5

x = 4

y = (4 - (3 * 4))/2

y = -4

which means that:

        x   |   y

1. |   0    |   2

2.|  -2    |   5

3.|    1    |   0.5

4.|    4   |   -4

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

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step-by-step explanation: