A triangle has vertices at (3, 3), (6, 15), and (3, -3). What are the coordinates of the orthocenter? A. (-69, 15)
B. (3.5, 3)
C. (4.2)
D. (9, 0)

The answer would be A) (-69, 15)

Solution:

Finding 1st and 2nd

m = (y2 - y1)/(x2 - x1)

m = (15 - 3 )/(6 - 3)

m = 12/3

y = 4x + b

3 = 3(3)+b

3=9+b

-9 -9

-6=b

Finding 3rd

repeat the above process for 1 and 2, so now use 2 and 3 in the equation.

m = -9/3

m=-3

y=-3x+b

15=-3(6)+b

b=-3

Step 2

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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a

step-by-step explanation: