What is the area of a triangle with vertices at (0,0), (0,4) and (4,5)?

8

Step-by-step explanation:

Let us label these coordinates for our own ease:

A(0,0)

B(0,4)

C(4,5)

Area= [Ax(By-Cy)+Bx(Cy-Ay)+Cx(Ay-By)]÷2

Area = [0(4-5)+0(5-0)+4(0-4)]÷2

Area= [0+0-16]÷2

Area = -8

But since the value can not be negative we have consider a modulus in the formula, thus the value is 8

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23