In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=84°, and HI = 69 feet. Find the length of IJ to the nearest tenth of a foot.

heyStep-by-step explanation:

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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