Write an equation in slope-intercept form for the line that goes through the points (2,3) and (7,-2).
a. y = 2x + 3
b. y = x + 1
c. y = -x + 5
d. y = 7x-2

c. y = -x + 5

Step-by-step explanation:

coordinates: (2,3) & (7, -2)

m(slope) = rise/run = (y2-y1) / (x2-x1)

= (-2-3) / (7-2)

= -5 / 5

= -1

therefore, y= -1x + b => y= -x + b

to find b:

taken coordinate: (2,3)

y= -x + b

3= -2 + b

3+2 = b

5 = b

(*even if we take the other coordinate, we'll still get the same value of b)

therefore y= -x + 5

dude   i don't even know. i've been trying for hours.

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.