Amari can spend at most $40 at the fair. It cost her $12 to enter the fair and $3 per ticket, t, to ride the rides.

i have no idea if you're looking for how many rides she can go on or the equation so i'll give you both lol.

Step-by-step explanation:

3t + 12 = 40

t represents the number of tickets (rides)

$12 is the entry fee.

$3 is the cost per ticket

to solve, use the subtraction property of equality. (subtract 12 from both sides)

3t + 12 - 12 = 40 - 12

3t = 28

divide each side by 3.

3t/3 = 28/3

28/3 = 9.3333...

amari can go on a maximum of 9 rides ($27) and stay within her budget of $40 or less.

$27 + $12 = $39.

she will have $1 left over.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1