the eighth grade class is going on a field trip to the Science Center they have up to $300 to spend on admission adult tickets cost $5 and student tickets cost $2 they have 12 adult chaperones write an inequality that could be used to determine how many students x could go on the field trip

ok so do 12 times 2 then take away that number from 300 and then divied it by 5

Step-by-step explanation:

50 adult tickets, 70 student

Step-by-step explanation:

Let number of Adult tickets sold  be x

    number of student tickets sold be y

Adult ticket costs $ 5, student ticket costs $ 3, Total collected $460,

5x+3y= 460eq 1

Total number of tickets sold = 120 so

x+y=120, Multiply eq by 3, we get 3x+3y=360, subtract it from eq 1

5x+3y=460

-3x-3y=-360

we get,

2x = 100

x=50

x+y = 120, x= 50 so y=70

No of Adult tickets sold = 50, No of Student tickets sold = 70

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)