Could ΔJKL be congruent to ΔXYZ? Explain. Yes, if JL ≅ XZ. Yes, if XZ = 10. No, because the hypotenuse of one triangle is equal in length to the leg of the other triangle. No, because the leg of one triangle is equal in length to the leg of the other triangle.

The answer is "No since one triangle's hypotenuse is equivalent in length to the triangle's leg".

Step-by-step explanation:

When its corresponding sides are congruent, there may be two triangles. Here a leg of the ΔXYZ measurements 10 (XY = 10). So, it must calculate upwards of 10 on its hypotenuse (the biggest hand in a rectangle hand).  

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x