24. Prove that cos( sin^-1)=squareroot 1-x^2?

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step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

the answer is c. ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

b: y = 2x + 2

step-by-step explanation:

y = 2x + 1

we want a line that is parallel, so it will have the same slope

the line is in the form y= mx+b, so the slope is 2

we have a slope and the y intercept (0,2)

since x is 0 we know the y point which is the y intercept

we can use y= mx+b to write the equation of the line

m is the slope and b is the y intercept

y = 2x +2