Diseases tend to spread according to the exponential growth model. In the early days of AIDS, the growth factor (i. E. Common ratio; growth multiplier) was around 1.9. In 1983, about 1800 people in the U. S. Died of AIDS. If the trend had continued unchecked, how many people would have died from AIDS in 2006?

4640933300 people would have died  from AIDS in 2006.

Step-by-step explanation:

Let the equation that models the growth in mortality because of AIDS be,

Where = Number of deaths after n years

= Deaths in first year

(1 + r) = Growth factor

n = number of years

Now we substitute the values in the equation,

(1 + r) = 1.9

n = Number of years = 2006 - 1983 = 23 years

     = 1800(2578296.28)

     = 4640933300

Therefore, with the same death rate 4640933300 people would have died  from AIDS in 2006.

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500