HELPP! The perimeter of a rectangle is 104 inches. The width is 6 inches less than 3 times the length. Find the width of the rectangle. Show each step and explain what was performed for each step.

The width of the rectangle is 37.5 inches and the length of the rectangle is 14.5 inches.

The perimeter of a rectangle is represented as follows:

perimeter = 2l + 2w

where

w = width

l = length

Therefore,

perimeter = 104 inches

let

the length = a

Therefore,

width = 3a - 6

Therefore,

104 = 2a + 2(3a - 6)

104 = 2a + 6a - 12

116  = 8a

a = 116 / 8

a = 14.5  inches

width = 3(14.5 ) - 6 = 37.5  inches

Therefore, the width of the rectangle is 37.5 inches and the length of the rectangle is 14.5 inches.

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Length of the rectangle = 14.5 inches

Width of the rectangle = 37.5 inches

Step-by-step explanation:

Let the length of a rectangle = a inches

Since, width of the rectangle is 6 inches less than 3 times the length,

w = 3a - 6

Perimeter of the rectangle = 104 inches

Formula to calculate the perimeter of a rectangle = 2(length + width)

104 = 2[a + (3a - 6)]

2a + 2(3a - 6) = 104 → [Starting equation]

8a - 12 = 104 → [Distributive property]

8a - 12 + 12 = 104 + 12 → [Addition property of equality]

a = → [Division property of equality]

a). width of the rectangle = (3a - 6) = 37.5 inches

b). length of the rectangle = 14.5 inches

answer is:

1.75 pounds

each side has a different length.  

step-by-step explanation: