Isabelle is plotting a pentagon on a grid. So far, she has plotted and connected the three points shown on the grid below. On a coordinate plane, lines connect points (negative 2, 4), (negative 3, 2), and (0, negative 2).

To complete the pentagon, she can choose only from the points below.

(2, 0), (–2, 0), (–2, 4), (2, 4)

How can Isabelle complete her pentagon?
Connect the point already at (0, –2) to a new point at (2, 0), and then connect
( 2, 0) to (–2, 4).
Connect the point already at (0, –2) to a new point at (–2, 0), and then connect ( –2, 0) to (–2, 4).
Connect the point already at (0, –2) to a new point at (–2, 0), connect ( –2, 0) to (2, 4), and then connect (2, 4) to (–2, 4).
Connect the point already at (0, –2) to a new point at (2, 0), connect
(2, 0) to (2, 4), and then connect (2, 4) to (–2, 4).

B. Connect the point already at (0, –2) to a new point at (–2, 0), and then connect ( –2, 0) to (–2, 4).

Step-by-step explanation:

1,645,493,059.35

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!