6 How many integers must be negative for the product of three integers to be negative? Explain. Find two different
groups of three integers whose product is -12.
Show your work.

Can sb plz help meh quick!!

Answer & Step-by-step explanation:

First of all, integers are the natural numbers, their opposites, and zero:

1.) Remember this: the positive symbol is made of two sticks. So, two negatives makes a positive:

If you have three integers, you would need all numbers to be negative for the product to be negative:

or:

When you multiply a negative and a positive, the result will always be nagative. So you can also have two positive numbers and one negative to have a negative product:

2.) Lets use both of the methods above:

and

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

14

step-by-step explanation:

14 x 3 = 42