Please help if you know how to do this please

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Step-by-step explanation:

Compared to vertex form ...

  y = a(x -h)^2 +k

we find that a=-3, (h, k) = (0, 0). That is, the vertex is (0, 0).

A parabola whose vertex is on the x-axis has that as its only x-intercept. (The x-intercept (vertex) is NOT in the solution set.)

The negative leading coefficient tells you the graph opens downward. The y < ( ) comparison tells you shading is below the boundary line, which is dashed. Below a downward-opening parabola is inside the parabola.

The two offered points are on the x-axis, so not in the solution set.

answer: what is the question you're trying to ask?

step-by-step explanation:

answer: your answer is a