Graph the first five ordered pairs for the sequence given by the formula an = 2+3(n - 1).

9514 1404 393

  (1, 2), (2, 5), (3, 8), (4, 11), (5, 14)

Step-by-step explanation:

Put the numbers 1 through 5 in the formula and do the computation:

  n = 1 (first term): 2 + 3(1 -1) = 2

  n = 2 (second term): 2 + 3(2 -1) = 5

  n = 3 (third term): 2 + 3(3 -1) = 8

  n = 4 (fourth term): 2 + 3(4 -1) = 11

  n = 5 (fifth term): 2 + 3(5 -1) = 14

The first 5 ordered pairs are (n, an) = (1, 2), (2, 5), (3, 8), (4, 11), (5, 14).

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Alternatively, you can compare the given formula to the formula for the general term of an arithmetic sequence:

  an = a1 + d(n -1)

Matching features of this formula with the given one, we see that ...

  a1 = 2, d = 3

That is, the first term is 2, and the common difference is 3. We can write down the sequence by starting with 2 and counting by 3s from there:

  2, 5, 8, 11, 14, 17, 20, 23, ...

Each "ordered pair" will consist of (term number, term value). Then the first 5 ordered pairs are ...

  (1, 2), (2, 5), (3, 8), (4, 11), (5, 14)

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

answer: 1, 3 and 5 are correct

step-by-step explanation: