Find the range of the function given the domain.
f(x) = x2 +2 ;D: {0, 0.25, 0.5, 0.75, 1}

{2, 2.0625, 2.25, 2.5625, 3}

Step-by-step explanation:

To find the range we can simply plug in the values of the domain and solve for the range. (The domain is the x-values)

Assuming x2 means x^2, we can plug in 0, 0.25, 0.75, 0.5, and 1 for x

0^2+2=2

0.25^2+2=0.0625+2=2.0625

0.5^2+2=0.25+2=2.25

0.75^2+2=0.5625+2=2.5625

1^2+2=1+2=3

Thus, the range is {2, 2.0625, 2.25, 2.5625, 3}

4x and 6y

im not sure though

b mark me branliest thx

step-by-step explanation: