Point A is located at –11. Point B is 5 less than Point A. Where is B located?

We know that point A is at -11, and B is 5 less than it, so we only have to substract 5 to -11, and see what we get by doing this operation:

-11 - 5 = -16

So now, we know that point A is located at -11 and we also know point B is located at -16

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

b mark me branliest thx

step-by-step explanation: