I NEED HELP I AM STUPID SO I DONT GET THIS HERE IS THE QUISTION 4-x-6(x+5)=15 HE ALSO SAID THIS - Students will determine whether an equation has 0, Infinite, or 1 solution, and if 1, find it. I ADDED A SCREEN SHOT OF QUISTION PLS HELP ME OR I AM FAILING THIS CLASS

im pretty sure it has two real solutions

Step-by-step explanation:

1. simplify the equation given

  (4x - 6)(x + 5) = 15

     4x^2 + 20x - 6x - 30 = 15

        4x^2 + 14x - 45 = 0

2. find the discriminant (b^2 - 4ac); (a = 4, b = 14, c = -45)

  14^2 - (4 x 4 x -45)

     196 - (-720)

        916

  the discriminant is positive, so this equation has 2 real solutions

to find the solutions, factor the bolded equation (if you need help factoring, let me know!)

based on context clues you gave i'm assuming the answer would be c.

ιт ιѕ (9χ^5+10)(81χ^10-90χ^5+100)

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ уσυ συт тσ∂α