The weight of a batch of pumpkins harvested from a local farm follows a normal distribution with a mean of 20 lb and a standard deviation of 3 lb. Find the probability that a randomly selected pumpkin weighs more than 24 lbs.

The probability that a randomly selected pumpkin weighs more than 24 lbs is 0.091211

Step-by-step explanation:

We solve this using z score formula

z-score is is z = (x-μ)/σ

where x is the raw score = 24lbs

μ is the population mean = 20Ibs

σ is the population standard deviation = 3Ibs

z = 24 - 20/3

z = 1.33333

The Probability value from Z-Table:

P(x ≤ 24) = P(x < 24) = P(z = 1.33333)

= 0.90879

P(x > 24) = 1 - P(x<24)

= 1 - 0.90879

= 0.091211

Therefore, the probability that a randomly selected pumpkin weighs more than 24 lbs is 0.091211

one set of data has more variation than the other. hope this !