Historically, 2 percent of the stray dogs in Southfield are unlicensed. On a randomly chosen day, the Southfield city animal control officer picks up seven stray dogs. What is the probability that fewer than two will be unlicensed

Step-by-step explanation:

Given

Represent the proportion of unlicensed stray dog with p

Convert p to decimal

First we need to determine the proportion of licensed stray dogs.

Represent this with q

In probability,

Solve for q

The probabiliy is binomial and it is represented as thus:

Since we have that fewer than two is selected.

Substitute values for p, q and n

---Approximated

i wish i could you, i have no idea how to answer this

step-by-step explanation:

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12