IQ scores have a mean of 100 and a standard deviation of 15. Kate has an IQ of 121. (a) What is the difference between Kate's IQ and the mean

(a) The difference between Kate's IQ and the mean is 21

(b) The z score is 1.4

Step-by-step explanation:

Here is the complete question:

IQ scores have a mean of 100 and a standard deviation of 15. Kate has an IQ of 121. (a) What is the difference between Kate's IQ and the mean (b) Convert Kate's IQ score to a z score.

Step-by-step explanation:

(a) To determine the difference between Kate's IQ and the mean, this can be done by subtracting the mean from Kate's IQ.

Mean = 100

Kate's IQ = 121

Difference between Kate's IQ and the mean = 121 - 100 = 21

Hence, the difference between Kate's IQ and the mean is 21.

(b) To convert Kate's IQ score to a z score,

z score is given by the formula

Where is the score

is the mean

and is the standard deviation

From the question,

= 121

= 100

= 15

Then, the z score is

z = 1.4

Hence, the z score is 1.4.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

d.) 48 units

step-by-step explanation: