Ronald has a 10% solution of the fertilizer Super Grow. How much pure Super Grow should he add to the mixture to get 36 oz of a 12.5% concentration?

1 oz

Step-by-step explanation:

Given that:

% solution of super grow fertilizer = 10%

To obtain mixture of 36oz of a 12.5% concentration

Let oz of pure supergrowth to be added = s

(Initial % * (36 - s) + s) / 36 = target concentration

(10% * (36 - s) + s) / 36 = 12.5%

(0.1(36 - s) + s) / 36 = 0.125

Cross multiply:

0.1(36 - s) + s =. 0.125 * 36

3.6 - 0.1s + s = 4.5

3.6 + 0.9s = 4.5

0.9s = 4.5 - 3.6

0.9s = 0.9

s =. 0.9/0.9

s = 1

Hence, 1 oz of pure supergrowth should be added to the 10% solution to get 36 oz of a 12.5% concentration.

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5