3. In the same opera theater personal balcony sections with three rows of seating are being mapped as well. In these sections there must be an odd number of seats in each row and each row must have two more seats
than the one before it. The last stipulation is that the front row must have one quarter the total seats in the
back 2 rows combined. How many seats will be in each row?

Number of seats in first row = 2

Number of seats in 2nd row = 4

Number of seats in 3rd row = 6

Step-by-step explanation:

Let's say number of seats in first row is x.

Now we are told that each row must have two more seats

than the one before it.

Thus, the remaining 2 rows have;

(x + 2) and (x + 4) seats respectively.

We are told that that the front row must have one quarter the total seats in the

back 2 rows combined.

Thus;

x = ¼((x + 2) + (x + 4))

Multiply both sides by 4 to give;

4x = x + 2 + x + 4

4x = 2x + 4

4x - 2x = 4

2x = 4

x = 4/2

x = 2

Thus;

Number of seats in first row = x = 2

Number of seats in 2nd row = (x + 2) = 2 + 2 = 4

Number of seats in 3rd row = (x + 4) = 2 + 4 = 6

do i do it on a graph?

step-by-step explanation:

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195