Acontractor wishes to build 9 houses, each different in design. in how many ways can he place these houses on a street if 6 lots are on one side of the street and 3 lots are on the opposite side?

362880

Step-by-step explanation:

Given : A contractor wishes to build 9 houses, each different in design.

he place these houses on a street if 6 lots are on one side of the street and 3 lots are on the opposite side.

Choices to arrange first lot = 9

After first house is designed , Choices to arrange second lot = 8

After second house is designed , Choices to arrange third lot = 7

and so on.....

So the total number of ways to arrange 9 lots will be :-

Hence, the required number of ways =362880

5/12, or 5: 12

step-by-step explanation:

susie has 7 apples