Write a possible equation for a polynomial whose graph has horizontal intercepts at x = 2,-1,-3. help

y = (x - 2)(x + 1)(x + 3)

Step-by-step explanation:

horizontal intercepts at x = 2, -1, -3

->  y = 0 when x = 2, x = -1, and x = -3

Think x minus what equals y?

1. y is 0 and x is 2 -> 0 = (2 - 2) -> y = (x - 2)

2. y is 0 and x is -1 -> 0 = (-1 - (-1)) -> y = (x + 1)

3. y is 0 and x is -3 -> 0 = (-3 - (-3)) -> y = (x - 3)

so the equation is y = (x - 2)(x + 1)(x + 3)

since y = 0 when x = 2, x = -1, and x = -3

john earns $14.00 for two hours of work.

25 questions , because they start with 100.  

350-100=250 .  

. 250/10=25

step-by-step explanation:

first take off 100, then what x 10 = 250? that is your answer. (25)