A ball thrown straight up in the air travels 90 inches in the first tenth of a second. In the next tenth of a second the ball travels 85 inches. After each additional tenth of a second, the ball travels 5 inches less than it did during the preceding tenth of a second. How long will it take before the ball starts coming back down? What is the total distance that the ball has traveled once it reaches its maximum height?

855

Step-by-step explanation:

1.9 seconds is 19 tenths, so that means we add using the information given, which is that the ball travels 5 fewer inches every tenth of a second:

Time | Inches traveled

0.1     | 90

0.2    | 85

0.3    | 80

0.4    | 75

0.5    | 70

0.6    | 65

0.7    | 60

0.8    | 55

0.9    | 50

1.0     | 45

1.1      | 40

1.2     | 35

1.3     | 30

1.4     | 25

1.5     | 20

1.6     | 15

1.7     | 10

1.8     | 5

1.9     | 0

90+85+80+75+70+65+60+55+50+45+40+35+30+25+20+15+10+5+0=855

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5

5

10

15

20

25

30

35

40

45

50

55