An urn contains nine blue balls and seven yellow balls. If three balls are selected randomly without being replaced, what is the probability that of the balls selected, one of them will be blue and two of them will be yellow?

Step-by-step explanation:

Given

Required

Determine the probability that one of the balls is blue while others is yellow

The order of selection may be any of these three:

Yellow, Yellow, Blue or Yellow, Blue, Yellow or Blue, Yellow, Yellow

Solving Yellow, Yellow, Blue

Solving Yellow, Blue, Yellow

Solving Blue, Yellow, Yellow

Hence:

The required probability is:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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