Regina buys materials to make watches for a jewelry fair. The materials are sold separately; there are 6 watch faces sold per package and 10 watch bands sold per package. What is the LEAST number of watches Regina can make WITHOUT having any supplies left over?

The LEAST number of watches Regina can make WITHOUT having any supplies left over is 30 watches

Step-by-step explanation:

Regina buys materials to make watches for a jewelry fair. The materials are sold separately; there are 6 watch faces sold per package and 10 watch bands sold per package. What is This question has to do with Lowest Common

Step 1

We find and list multiples of each number until the first common multiple is found. This is the lowest common multiple.

Multiples of 6:

6, 12, 18, 24, 30, 36, 42

Multiples of 10:

10, 20, 30, 40, 50

Therefore,

LCM(6, 10) = 30

The LEAST number of watches Regina can make WITHOUT having any supplies left over is 30 watches

30

Step-by-step explanation:

Given that :

6 watch faces per package and 10 watch bands per package :

To obtain the least number of watches that can be made without any supplies left over, we take the Least common multiple ( L. C. M) Of 6 and 10

_2__|6___|10

_3__|3___|5

_5__|1___ |5

|1___|1

Lowest common multiple = (2 * 3 * 5). = 30

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.