Mathematics, 21.10.2020 16:01 elainestorm9633
Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5%5%? Round your answer to four decimal places.
Answers: 1
is the sample proportion of persons with a college degree.![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )](/tpl/images/0827/7925/1d98e.png)
![\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))](/tpl/images/0827/7925/5acb2.png)
![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]](/tpl/images/0827/7925/9134e.png)
![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]](/tpl/images/0827/7925/d2a65.png)
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Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, w...
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