Three assembly lines Alpha, Beta, and Gamma make the same power transistor. Each of the assembly lines has its own level of efficiency. Resulting in inventory having 20% of the transistors from Alpha, 50% from Beta, and the remaining 30% from Gamma. Further the probability a transistor from Alpha will be defective is 0.02, a transistor from Beta will be defective is 0.06, and a transistor from Gamma will be defective is 0.04. If a random transistor from inventory is defective, what is the probability it came from Bet

P [ β / Def]  = 0,6521     or      65,21 %

Step-by-step explanation:

Tree diagram:

0,20 (α)       Defective  0,02

0,50 (β)       defective   0,06

0,30 (γ)       defective    0,04

According to Baye´s Theorem

P [ A/B]  = P[A] * P [ B/A] / P[B]

if we call

β = A   and  Defective = B       then  P[β] = P[A]  and P[Defective] = P[B]

we get :

P [ β / Def]  = P[β] * P [ def./β] / P[def]

Then

P[β] = 0,5

P[def/β] = 0,06

P [Defective] = 0,02* 0,2 + 0,06*0,5 + 0,04*0,3

P [Defective] = 0,004 + 0,03 + 0,012

P [Defective] = 0,046

P [ β / Def]  = 0,5 * 0,06 / 0,046

P [ β / Def]  = 0,6521     or      65,21 %

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98

so then what are you asking?

step-by-step explanation: