Suppose you have a 6-face unfair dice with numbers 1,2,3,4,5,6 on each of its faces. If the probability distribution of throwing a number up is as follows: 1 with probability 1/12 2 with probability 1/12 3 with probability 1/12 4 with probability 1/12 5 with probability 1/12 6 with probability 7/12 What are the mathematical expectation and variance of the dice based on the above probability distribution

Expectation is equal to 4.75

Variance is equal to 3.02

Step-by-step explanation:

Consider the attached image.

Let denotes each of the outcome.

Expectation = ∑

∑

Variance  

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

452,489 to the nearest thousand is 452,000