Three consecutive integers such that 10 less than their sum is 80

20,30,31

Step-by-step explanation:

Let the numbers be x,x+1,x+2

x+x+1+x+2=90

3x+3=90

3x=90-3

3x=87

x=87/3

x=29

x+1=30

x+2=31

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

i think the correct option is the second option.