No 2 please. Quick. HELP ASAP

Part A

We have 20 cards, 4 of which are kings (one of each suit). The probability of getting a king on the first draw is 4/20 = 1/5.

Part B

We have 20-4 = 16 cards that aren't a king out of 20 total.

The probability of getting a non-king card is 16/20 = 4/5

After selecting the first card and not putting it back, we have 20-1 = 19 cards left. Four of which are a king, so 4/19 represents the probability of getting a king on this draw.

So (4/5)*(4/19) = 16/95 is the probability of getting a king on the second draw where the first draw is not a king.

Part C

16/20 is the probability of getting no kings on the first draw

15/19 is the probability of getting no kings on the second draw (notice I stepped the values down by 1)

14/18 is the probability of getting no kings on the third draw

Multiplying out the fractions gives

(16/20)*(15/19)*(14/18) = 28/57

I skipped a few steps when multiplying the fractions but you get the idea.

The probability of drawing 3 cards, none of which are a king, is 28/57

Subtract this from 1 to get the complementary probability

1-(28/57) = 57/57 - 28/57 = (57-28)/57 = 29/57

This works because we have two choices: either we get no kings, or we get at least one king. So that's why the two events are complementary and their probabilities add to 1.

lol we need to see what the question is asking about

step-by-step explanation:

nada

step-by-step explanation: