Please help on this: Given: 4c-d = f, d = c-e, f = d + e; Prove: 3c = d

Step-by-step explanation:

Given the equations:

4c-d = f   1

d = c-e 2

f = d + e 3

Substitute 2 into 1

4c -(c-e) = f

4c -c + e =f

3c + e = f 4

Substitute equation 3 into 4:

3c+e = d+e

subtract e from both sides

3c+e-e = d+e-e

3c = c (Proved)

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!