Select each inequality that 0 is a solution to. -3(y - 1) ≥ 3

2y - 4 0

- y -1 > 0

y + 8 ≤ 2y + 8

select the first and last options.

Step-by-step explanation:

1.

-3(y - 1) >= 3

-3y + 3 >= 3

-3y >= 0

y >= 0

0 is a solution

2.

2y - 4 > -4

2y > 0

y > 0

0 is not a solution

3.

-y - 1 > 0

-1 > y

0 is not a solution

4.

y + 8 <= 2y + 8

8 - 8 <= 2y - y

0 <= y

0 is a solution

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

your answer would be 12