Mr. Shaw graphs the function f(x) = -5x + 2 for his class. The line contains the point (-2, 12). What is the point-slope form of the equation of the line he graphed?
Oy - 12 = -5(x + 2)
Oy - 12 = 2(x + 2)
O y + 12 = 2(x - 2)
O y + 12 = -5(x - 2)

The first choice is correct. y-12=-5(x+2)

Step-by-step explanation:

Point-Slope Form of a Line

The point-slope form of the equation of a line is:

y-k=m(x-h)

Where m is the slope and (h,k) is a point through which the line passes.

The equation of the line in slope-intercept form is:

y=mx+b

Where b is the y-intercept.

Mr. Shaw graphs the function y=f(x)=-5x+2

The coefficient of the x can be identified as the slope m=-5. We are given the point (-2,12) to build the point-slope form of Mr. Shaw's line as follows:

y-12=-5(x+2)

The first choice is correct. y-12=-5(x+2)

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8