The local nursery is waiting for its spring annuals to be delivered, and 20% of the plants ordered are petunias. If the first truck contains 120 plants packed at random, what is the probability that no more than 30 plants are petunias?

0.9147

Step-by-step explanation:

Given: 20% of the plants ordered are petunias.

Let p = 20% = 0.2

Sample size: n = 120

If they follow normal distribution, then mean = np = 120x 0.2 = 24

Standard deviation =

The  probability that no more than 30 plants are petunias :

Hence, the probability that no more than 30 plants are petunias = 0.9147

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

hi there!

the answer will be d: 2